Resposta:
Aplicar D = m / V onde D = de m =
massa V = volume
Dados
D agua = 1g / c * m ^ 3
Volume da a gua=1,5L=1500cm^ 3 =>m=D^ * V
1g/cm^ 3 *1500cm^ 3 ==>m=1500g
Dgelo = 0, 92g / c * m ^ 3
m gelo = magua = 1500g
Vgelo = ?
V = m / D
V = 1500g / 0, 92g / c * m ^ 3
V=1630cm^ 3 ==>1,63L
