[tex] x {}^{2} + 2x - 8 = 0 = \\ x {}^{2} + 2x - 4x - 8 = 0 = \\ x \times (x + 2) - 4x - 8 = 0 = \\ x \times (x + 2) - 4 - 8 = 0 = \\ (x + 2) \times (x - 4) = 0 = \\ x + 2 = 0 = \\ x - 4 = 0 = \\ x = - 2 = \\ x = 4 \\ x_{1} = - 2 \: , \: x_{2} = 4 \\ \\ \\ ☆
|| ASS: Blues / 02|09|21 / às 20:53[/tex]
