Resposta:
[tex]2-3.\{2-[(-3+2)(3-5)]\}-1=\\ \\ 2-3.\{2-[(-1)(-2)]\}-1=\\ \\ 2-3.\{2-[+2]\}-1=\\ \\ 2-3.\{2-2\}-1=\\ \\ 2-3.\{0\}-1=\\ \\ 2-0-1=\\ \\ 2-1=\boxed{1}[/tex]
2-3{2-[(-3 +2)(3 - 5)]}-1
=2−3(2−−1(3−5))−1
=2−3(2−(−1)(−2))−1
=2−3(2−2)−1
=2−(3)(0)−1
=2−0−1
=2−1
=1
Explicação passo a passo:
