Resposta :
Resposta:
Calculemos a concentração de [tex]H_{3}O^{+}:[/tex]
[tex]pH = -log[H_{3}O^{+}]\\\\log[H_{3}O^{+}] = -2,34\\\\\[[H_{3}O^{+}] = 10^{-2,34}\\\\\[[H_{3}O^{+}] = 4,57\,.\,10^{-3}\,\,M.[/tex]
Resposta:
Calculemos a concentração de [tex]H_{3}O^{+}:[/tex]
[tex]pH = -log[H_{3}O^{+}]\\\\log[H_{3}O^{+}] = -2,34\\\\\[[H_{3}O^{+}] = 10^{-2,34}\\\\\[[H_{3}O^{+}] = 4,57\,.\,10^{-3}\,\,M.[/tex]