Resposta:
Explicação passo a passo:
a
(2x+3)²=
(2x+3)(2x+3)=
4x²+6x+6x+9=
4x²+12x+9
b
(3y²+2x)(3y²-2x)=
9y^4-6xy^2+6xy^2-4x^2=
9y^4-4x^2
[tex]a) \\ (2x + 3) {}^{2} \\ (2x) {}^{2} + 2 \: . \: 2x \: . \: 3 + 3 {}^{2} \\ \boxed{\boxed{\boxed{4x {}^{2} + 12x + 9}}} \\ [/tex]
[tex]b) \\ (3y {}^{2} + 2x) \: . \: (3y {}^{2} - 2x) \\ (3y {}^{2} ) {}^{2} - (2x) {}^{2} \\ \boxed{\boxed{\boxed{9y {}^{4} - 4x {}^{2} }}} \\ [/tex]
atte. yrz
