Resposta :
Resposta:
a)CO²= 12+16+16=44g/mol
b)CaCO²= 40+12+16+16=84g/mol
c)NaOH=23+16+1=40g/mol
d)CaO=40+16=56g/mol
2)
P.V=nRt
12×24,4=n×0,082×173
n=12×24,4/0,082×173
n= 617,7moles
Resposta:
a)CO²= 12+16+16=44g/mol
b)CaCO²= 40+12+16+16=84g/mol
c)NaOH=23+16+1=40g/mol
d)CaO=40+16=56g/mol
2)
P.V=nRt
12×24,4=n×0,082×173
n=12×24,4/0,082×173
n= 617,7moles