Resposta :
Resposta:
[tex]x {}^{2} + 10x + 25 = 0 \\ a = 1 \: b = 10 \: c = 25 \\ delta = b {}^{2} - 4ac \\ delta = 10 {}^{2} - 4.1.25 \\ delta = 100 - 100 \\ delta = 0 \\ x = \frac{ - b + - \sqrt{delta} } 2a{} \\ \\ x = \frac{ - 10 + - 0}{2.1} \\ \\ x1 = \frac{ - 10 + 0}{2} = - 5 \\ \\ x2 = \frac{ - 10 - 0}{2} = - 5[/tex]