Resposta :
[tex]10x^2-1000=0\\\\10x^2=0+1000\\\\10x^2=1000\\\\x^2=\frac{1000}{10}\\\\x^2=100\\\\x=\pm\sqrt{10}\\\\S=\{-10,\ 10\}[/tex]
Sendo x' = -10 e x'' = 10, temos que:
(x')² + (x'')² = (-10)² + (10)² = 100 + 100 = 200
(x')² + (x'')² = 200
[tex]10x^2-1000=0\\\\10x^2=0+1000\\\\10x^2=1000\\\\x^2=\frac{1000}{10}\\\\x^2=100\\\\x=\pm\sqrt{10}\\\\S=\{-10,\ 10\}[/tex]
Sendo x' = -10 e x'' = 10, temos que:
(x')² + (x'')² = (-10)² + (10)² = 100 + 100 = 200
(x')² + (x'')² = 200