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Respondido

qual o lim de: (x^n+1) / x^n quando x tende ao infinito

Resposta :

CYBERKIRITOON

[tex]\Large\boxed{\begin{array}{l}\displaystyle\sf\lim_{x \to \infty}\dfrac{x^{n+1}}{x^n}\\\\\displaystyle\sf \lim_{x \to \infty}\dfrac{\diagup\!\!\!\!x^n\cdot x}{\diagup\!\!\!\!x^n}\\\\\displaystyle\sf \lim_{x \to \infty} x=\infty\end{array}}[/tex]

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