Resposta:
As raízes são -3 e 1
Explicação passo a passo:
[tex]\begin{array}{l}\Delta =b^{2} -4ac=2^{2} -4\cdotp 1\cdotp ( -3) =16\\\\x=\frac{-b\pm \sqrt{\Delta }}{2a} =\frac{-2\pm 4}{2\cdotp 1} \Longrightarrow \boxed{x=1\lor x=-3}\\\\\therefore \boxed{\boxed{S=\{x\in \mathbb{R} |x=-3\lor x=1\}}}\end{array}[/tex]
