Resposta:
[tex]3 * A + B^{t} = \left[\begin{array}{ccc}6&14\\-1&-11\end{array}\right][/tex]
Explicação passo a passo:
Calculemos a transposta de B, inicialmente
Lembre-se que a transposta transforma as linhas em colunas.
[tex]B = \left[\begin{array}{cc}6&11\\-10&1\end{array}\right][/tex]
[tex]B^t = \left[\begin{array}{ccc}6&-10\\11&1\end{array}\right][/tex]
Segue que
[tex]\\3 * \left[\begin{array}{ccc}0&1\\3&-4\end{array}\right] + \left[\begin{array}{ccc}6&11\\-10&1\end{array}\right][/tex]
[tex]3 * A + B^{t} = \left[\begin{array}{ccc}0&3\\9&-12\end{array}\right] + \left[\begin{array}{ccc}6&11\\-10&1\end{array}\right] = \left[\begin{array}{ccc}6&14\\-1&-11\end{array}\right][/tex]
