Resposta :
[tex]0,899\cong \frac{9}{10}\\0,101\cong \frac{1}{10}\\\\(\frac{81}{100}-\frac{1}{100})\frac{1}{2}=\frac{80}{100}*\frac{1}{2}=\frac{80}{200}=\frac{2}{5}=0,4[/tex]
[tex]0,899\cong \frac{9}{10}\\0,101\cong \frac{1}{10}\\\\(\frac{81}{100}-\frac{1}{100})\frac{1}{2}=\frac{80}{100}*\frac{1}{2}=\frac{80}{200}=\frac{2}{5}=0,4[/tex]