Resposta :
Resposta:
[tex] {(x - 5)}^{2} = 2x \times (x - 5) \\ {x}^{2} - 10x + 25 = 2 {x}^{2} - 10x \\ {x}^{2} - 10x + 25 - 2 {x}^{2} + 10 = 0 \\ - {x}^{2} - 10x + 35 = 0 \times ( - 1) \\ {x}^{2} + 10x - 35 = 0[/tex]
a = 1
b = 10
c = -35
Resposta:
[tex] {(x - 5)}^{2} = 2x \times (x - 5) \\ {x}^{2} - 10x + 25 = 2 {x}^{2} - 10x \\ {x}^{2} - 10x + 25 - 2 {x}^{2} + 10 = 0 \\ - {x}^{2} - 10x + 35 = 0 \times ( - 1) \\ {x}^{2} + 10x - 35 = 0[/tex]
a = 1
b = 10
c = -35