Resposta :
Resposta:
[tex]\frac{\frac{x+1}{x-2}+\frac{x-3}{x+2}}{\frac{2x^2-2x+8}{x-2}}\\\\\frac{\left(\frac{x+1}{x-2}+\frac{x-3}{x+2}\right)\left(x-2\right)}{2x^2-2x+8}\\\\\frac{\frac{2x^2-2x+8}{\left(x-2\right)\left(x+2\right)}\left(x-2\right)}{2x^2-2x+8}\\\\\frac{\frac{2x^2-2x+8}{x+2}}{2x^2-2x+8}\\\\\frac{2x^2-2x+8}{\left(x+2\right)\left(2x^2-2x+8\right)}\\\\\frac{1}{x+2}\\\\Letra \ b) \frac{1}{x+2}[/tex]
Qualquer duvida me chame!!!