Resposta :
Resposta:
[tex]a_1_0=64[/tex]
Explicação passo-a-passo:
[tex]PA(a_1,a_2,a_3,a_4,...)\\\\a_2-a_1=a_3-a_2\\\\x-3-10=x+3-(x-3)\\\\x-3-10=x+3-x+3\\\\x =6+3+10\\\\x=19\\\\PA(10,19-3,19+3,...)\\\\PA=(10,16,22,...)\\\\a_1_0=a_1+9r\\\\r=16-10=6\\\\a_1)=10+9.6\\\\a_1_0=10+54\\\\a_1_0=64[/tex]