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Determine o valor de x na equação logarítmica, log de 3 na base 5 + log de ( x +2 ) na base 5 = 2 ​

Resposta :

[tex]\log_{a}b+\log_{a}c=\log_{a}b.c[/tex]

[tex]\log_{5}3+\log_{5}(x+2)=2\\\\\log_{5}[3.(x+2)]=2\\\\\log_{5}(3x+6)=2\\\\5^2=3x+6\\\\25=3x+6\\\\19=3x\\\\x=\frac{19}{3}[/tex]