Resposta :
[tex]\large\boxed{\begin{array}{l}\sf3^{-1}=\dfrac{1}{3}\\\underline{\rm de~modo~geral\!:}\\\sf\bigg(\dfrac{b}{a}\bigg)^{-n}=\bigg(\dfrac{a}{b}\bigg)^n\end{array}}[/tex]
[tex]\large\boxed{\begin{array}{l}\sf3^{-1}=\dfrac{1}{3}\\\underline{\rm de~modo~geral\!:}\\\sf\bigg(\dfrac{b}{a}\bigg)^{-n}=\bigg(\dfrac{a}{b}\bigg)^n\end{array}}[/tex]