Resposta:
[tex]\textsf{Leia abaixo}[/tex]
Explicação passo-a-passo:
[tex]\mathsf{\dfrac{11 + 2i}{2 - i} \times \dfrac{2 + i}{2 + i} = \dfrac{22 + 11i + 4i + 2i^2}{4 + 2i - 2i - i^2}}[/tex]
[tex]\mathsf{\dfrac{22 + 11i + 4i + 2i^2}{4 + 2i - 2i - i^2} = \dfrac{22 + 11i + 4i + 2(-1)}{4 + 2i - 2i - (-1)}}[/tex]
[tex]\mathsf{\dfrac{22 + 11i + 4i + 2(-1)}{4 + 2i - 2i - (-1)} = \dfrac{22+ 11i + 4i - 2}{4 + 2i - 2i + 1}}[/tex]
[tex]\mathsf{\dfrac{20+ 15i}{5} = 4 + 3i}[/tex]
[tex]\boxed{\boxed{\mathsf{\dfrac{11 + 2i}{2 - i} = 4 + 3i}}}\leftarrow\textsf{letra D}[/tex]
