[tex]v_0=10\ m/s\\ a=6\ m/s^2\\ x_0=25\ m\\\\ \boxed{x=x_0+v_0t+\dfrac{1}{2}at^2}[/tex]
[tex]x(t)=25+10t+\dfrac{1}{2}(6)t^2\ \therefore\ \boxed{x(t)=25+10t+3t^2}[/tex]
[tex]t=14\ \to\ x(14)=25+10(14)+3(14)^2\ \therefore[/tex]
[tex]\boxed{x(14)=753\ m}[/tex]
