gente me ajuda please

Explicação passo-a-passo:
(-1/3)^-2 : (-1/3)^9
As bases são iguais portanto:
(-1/3)^-2-9
(-1/3)^-11
ou seja:
[tex](-\frac{1}{3})^{-11}[/tex]
[tex]\frac{(\frac{-1}{3})^{-2}}{(\frac{-1}{3})^9}\\\\\frac{(\frac{-3}{1})^2}{(\frac{-1}{3})^9}\\\\\frac{\frac{3^2}{1}}{\frac{-1}{3^9}}\\\\\frac{3^2.3^9}{-1}\\\\\frac{3^{11}}{-1}\\\\(\frac{-1}{3})^{-11}[/tex]