Dados:
[tex]e=2\times10^{10}\ \mathrm{el\acute{e}trons}\\ n=1.6\times10^{-19}\ C\ \text{(carga fundamental)}[/tex]
Explicação:
[tex]\boxed{Q=ne}\ \therefore\ Q=1.6\times10^{-19}\big(2\times10^{10}\big)\ \therefore[/tex]
[tex]Q=3.2\times10^{-9}\ C\ \therefore\ \boxed{Q=3.2\ nC}[/tex]
