RICHARDSOUSA88ON RICHARDSOUSA88ON Matemática Respondido Dadas as matrizes A = [2 -1] e B = [1 2] e as escalas k1 = 3 e k2= -1, prove que: 3 0 -1 1a) k1(A+B) = k1A + k1Bb) (A+B)^T = A^T + B^Tc) (k2A)^T=k2A^Td) AB ≠ BAe) AI = IA =Af) (AB)^T=B^TxA^T