Resposta:
a) 50° F → °C ⇒ [tex]\frac{TC}{5} = \frac{TF-32}{9}[/tex] =
[tex]\frac{TC}{5}=\frac{50-32}{9}[/tex]
9(TC) = 5(50-32)
9TC = 5*18
TC = [tex]\frac{90}{9}[/tex]
Tc = 10 °C
b) -40 °C → F
[tex]\frac{TC}{5} = \frac{TF-32}{9}[/tex]
[tex]\frac{-40}{5}=\frac{TF-32}{9}[/tex]
9(-40) = 5(TF-32)
-360 = 5(TF-32)
[tex]\frac{-360}{5} = TF-32[/tex]
-72 = TF-32
-72+32 = TF
TF = 40 °F
c)393 K→ °C
[tex]\frac{TC}{5}=\frac{TK-273}{5}[/tex]
[tex]\frac{TC}{5}= \frac{393-273}{5}[/tex]
TC = 120 °C
d)30 °C → K
[tex]\frac{TC}{5}=\frac{TK-273}{5}[/tex]
[tex]\frac{30}{5}= \frac{TK-273}{5}[/tex]
30 = TK-273
30+273 = TK
TK = 303 K
Explicação:
