Resposta :
[tex]\log_2 16+\log_4 8+\log_8 4=[/tex]
[tex]\frac{\log16}{\log2}+\frac{\log8}{\log4}+\frac{\log4}{\log8}=[/tex]
[tex]\frac{\log2^4}{\log2}+\frac{\log2^3}{\log2^2}+\frac{\log2^2}{\log2^3}=[/tex]
[tex]\frac{4\log2}{\log2}+\frac{3\log2}{2\log2}+\frac{2\log2}{3\log2}=[/tex]
[tex]4+\frac{3}{2}+\frac{2}{3}=[/tex]
[tex]\frac{24}{6}+\frac{9}{6}+\frac{4}{6}=[/tex]
[tex]\frac{37}{6}[/tex]