Resposta:
[tex](3x-\frac{1}{2} )(x^{2} +4)=3x^{3} +12x-\frac{x^{2} }{2} -\frac{4}{2} \\ \\ mmc=2\\ \\ \frac{6x^{3} +24x-x^{2}-4 }{2} =\frac{6x^{3}-x^{2}+24x-4 }{2}[/tex]
